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5x^2+20x-100=110
We move all terms to the left:
5x^2+20x-100-(110)=0
We add all the numbers together, and all the variables
5x^2+20x-210=0
a = 5; b = 20; c = -210;
Δ = b2-4ac
Δ = 202-4·5·(-210)
Δ = 4600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4600}=\sqrt{100*46}=\sqrt{100}*\sqrt{46}=10\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-10\sqrt{46}}{2*5}=\frac{-20-10\sqrt{46}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+10\sqrt{46}}{2*5}=\frac{-20+10\sqrt{46}}{10} $
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